A merry.,go-round with a a radius of R-1,94 m and moment of inertia I -211 kg-m2

Question

A merry.,go-round with a a radius of R-1,94 m and moment of inertia I -211 kg-m2 is spinning with an initial angular holds on to the rim of the merry-go-round. 1) What is the magnitude of the initial angular momentum of the merry-go-round? speed of ·1.69 rad/s in the counter clockwise direection when viewed from above. A person with mass m-77 kg and velocity v 4.1 m/s runs on a path tangent to the merry-go-round. Once at the merry- go-round the person jumps on and 356.59 You currently have 1 submissions for this question. Only 10 submission are allowed. You can make 9 more submissions for this question. -m is Submit 2) What is the magnitude of the angular momentum of the person 2 meters before she jumps on the merry-go-round? kg-m2/s Submit 612.458 You currently have 1 submissions for this question. Only 10 submission are allowed You can make 9 more submissions for this question. Your submissions: 612.458 Computed value: 612.458 Feedback: Correct Submitted: Monday, October 30 at 12:49 PM 3) What is the magnitude of the angular momentum of the person just before she jumps on to the merry-go-round? 612 458ke-m21s Subemit You currently have 1 submissions for this question. Only 10 submission are allowed. You can make 9 more submissions for this question. 4) What is the angular speed of the merry-go-round after the person jumps on? radis Submt 2.68 You currently have 3 submissions for this question. Only 10 submission are allowed You can make 7 more submissions for this question. S) Once the merry go-round travels at this new angular spood, with what force does the person need to hold on

Explanation / Answer

Given:

r = 1.94m

I = 211 kg.m2

w = 1.69 rad/s

m = 77kg

v = 4.1 m/s

1) L1 = I*w = ***356.59***

2) L2 = r x p = r*m*v =***612.458***

3) Exactly the same as question 2...***612.458***

4) w = (L1+L2)/(I+m*r^2) = ***1.935*...

5) a=(w^2)*r = 1.935^2*1.94 = 7.264,

F=m*a = ***559.31***

6) v= w*r = 1.935*1.94 = ***3.7539***

7) (L1+L2-L3)/I,

L3=m*v*r = 77*3.7539*1.94 = 560.76

(356.59 + 612.458 - 560.76)/211 = 1.935

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