A message can be delivered using 2 hops. BER = p = 10 -5 A] How many transmissio

ID: 2266653 • Letter: A

Question

A message can be delivered using 2 hops. BER = p = 10-5

A] How many transmissions/hop would it take to deliver the message if the message is 1 Mbit long?

B] How many transmissions/hop would it take to deliver the message if the message is segmented in 100-kbit packets?

C] How many transmissions/hop would it take to deliver the message if the message is segmented in 10-kbit packets?

D] How many bits would be transmitted in the three cases?

A.Total number of bits transmitted =

B.Total number of bits transmitted =

C.Total number of bits transmitted =

Answer:

A] If we transmit the entire mesasge, the probability that the message arrives correctly after the first hop is given by:

Pc = (1 - p)^L = (1 - 10^-5)^1000000

Here p is the bit error rate = 10^-5

L is the length of the message = 1 Mbit = 1000000 bits

Hence Pc = 1/3

So it will take 3 hops to deliver the message.

B] If the message is segmented in 100-kbit packets, it will take 2 hops to transmit the message.

C] If the message is segmented in 10-kbit packets, it will take 1 hop to transmit the message.

A. Total number of bits transmitted = Each hop will require 3 full message transmissions. For 3 hops, 1 Mbit * 3 = 3 Mbits will be transmitted.

B. Total number of bits transmitted = Each hop will require 3 full message transmissions. For 2 hops, 100 kbits * 2 = 200 kbits will be transmitted.

C. Total number of bits transmitted = Each hop will require 3 full message transmissions. For 1 hop, 10 kbits* 1 = 10 kbits will be transmitted.

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