A Potter’s wheel moves uniformly from rest to an angular speed of 0.19 rev/s in

Question

A Potter’s wheel moves uniformly from rest to an angular speed of 0.19 rev/s in 33.0 s. Find it’s angular acceleration in radians per second per second. Would doubling the angular acceleration during the given period have doubled final angular speed? A Potter’s wheel moves uniformly from rest to an angular speed of 0.19 rev/s in 33.0 s. Find it’s angular acceleration in radians per second per second. Would doubling the angular acceleration during the given period have doubled final angular speed?

Explanation / Answer

( 0.19 rev/sec )( 2 rad / rev )

= 1.1932 rad / sec

Uniform angular acceleration is change in angular velocity divided by change in time:
= / t
= ( 1.1932 rad / sec ) / ( 33 sec )
= 0.0361 rad / sec²

Yes, doubling to 0.0723rad / sec² would have resulted in a final angular velocity of 0.38 rev / sec. This is because
= ·t.

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