a block of mass m=79kg slides along a horizontal surface. The coefficient of fri

Question

a block of mass m=79kg slides along a horizontal surface. The coefficient of friction between the block and the surface is 0.29. The block has an initial speed of v0=22 ms in the positive x direction a) write an expression for the x component of the friction force the block experiences, Ff in terms of the given variables b) Whst is the magnitude of the friction force in N? c) Hoe far will the block travel in meters before coming to a rest? a block of mass m=79kg slides along a horizontal surface. The coefficient of friction between the block and the surface is 0.29. The block has an initial speed of v0=22 ms in the positive x direction a) write an expression for the x component of the friction force the block experiences, Ff in terms of the given variables b) Whst is the magnitude of the friction force in N? c) Hoe far will the block travel in meters before coming to a rest? a block of mass m=79kg slides along a horizontal surface. The coefficient of friction between the block and the surface is 0.29. The block has an initial speed of v0=22 ms in the positive x direction a) write an expression for the x component of the friction force the block experiences, Ff in terms of the given variables b) Whst is the magnitude of the friction force in N? c) Hoe far will the block travel in meters before coming to a rest? a) write an expression for the x component of the friction force the block experiences, Ff in terms of the given variables b) Whst is the magnitude of the friction force in N? c) Hoe far will the block travel in meters before coming to a rest?

Explanation / Answer

deceleration = gravity * cof
9.81 m/s/s*0.29 = 2.85 m/s/s

v=vo+at
0 = 22 - 2.85*t
2.85*t = 22
t = 7.72 sec

distance = do -1/2 at^t
d = 0 -1/2*(2.85)(7.72)^2
d = 84.93 meters

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