of the system is mi is 15kg. m2 is 1 kg and ms is 3 kg. Make sure to show the FB
ID: 1787219 • Letter: O
Question
of the system is mi is 15kg. m2 is 1 kg and ms is 3 kg. Make sure to show the FBD and summation of forces for each mass. 7. The arrow shows the movement of the system. Solve for the acceleration 30° 8. A box weighs one sixth as much on the surface of the moon as it does on earth. If the box weighs 30 N on earth and the radius of the moon is 1.738x10s m, solve the following (a) the mass of the box and (b) the mas of the moon. If the box is taken to a height of 160km above the surface of the moon, (c) what would the box's mass be now? (d) What would the box's weight be now? (e) What would the gravitational acceleration at this height be? mass of the earth 5.96x1024 kg: radius of the earth 6.37x106 m.Explanation / Answer
7)Let the tension in string connecting blocks m2 and m3 be T1 and in the string connecting blocks m1 and m2 be T2
15*9.8sin30 - 0.2*15*9.8cos30-T2=ma
or, 73.5-25.46-T2=15a
Or, T2+15a = 48.04...(i) T2-4a=29.4
T2-T1 = 1*a
T2-T1=a...(ii)
T1-(3*9.8)=3a
T1-29.4=3a..(iii)
Solving equations (i),(ii) and (iii), we get
a=0.98 m/s2
8) a) Weight ob box on earth = 30 N
mass of box = 30/9.8=3.06 kg
b)acceleration due to gravity on moon = 9.8/6=1.633 m/s2
Let the mass of moon be M
6.674*10-11*M/(1.738*106)2 = 1.633
M = 7.39*1022 kg
c)the box's mass is independent of the planet .The mass is 3.06 kg
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