Exercise 30.24 Part A In the following figure (Figure 1), R = 16.112 and the bat

Question

Exercise 30.24 Part A In the following figure (Figure 1), R = 16.112 and the battery emf is 6.29 V With switch S2 open, switch S1 is closed After several minutes, S1 is opened and At 2.11 ms after S1 is opened, the current has decayed to 0.294 A. Calculate the inductance of the coil Express your answer to three significant figures and include the appropriate units. is close 1234 L= 1 Value Units Submit My Answers Give Up Part B How long after S1 is opened will the current reach 1.00% of its original value? Express your answer to three significant figures and include the appropriate units 1234 1 Value Units Submit My Answers Give Up Provide Feedback Continue Figure of 1 S2

Explanation / Answer

We know that after being connected in circuit for a long time, inductor offers no resistance to circuit

I max = 6.29 V/ 16.1=0.3906 A

once s1 is opened, inductor will start decaying through R

I= I max e^ ( -R/L) t

0,294 = 0.3906 e ^( -16.1/ L) 2.11 x 10^-3

taking anti-log on both sides

(-0.284) = ( -16.1/ L) ( 2.11 x 10^-3)

L = ( 16.1/ 0.284) ( 2.11 x 10^-3) = 0.1196 H

b) 1/100 = e^ ( -16.1/0.1196) t

taking anti log on both sides

-4.605 = ( -134.615) t

t= 29.23 seconds apprx

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