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Exercise 30.38 In an L - C circuit, C = 3.18 ? F and L = 89.0mH . During the osc

ID: 1378605 • Letter: E

Question

Exercise 30.38

In an L-C circuit, C = 3.18?F and L = 89.0mH . During the oscillations the maximum current in the inductor is 0.846mA .

Part A

What is the maximum charge on the capacitor?

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Part B

What is the magnitude of the charge on the capacitor at an instant when the current in the inductor has magnitude 0.496mA ?

Exercise 30.38

In an L-C circuit, C = 3.18?F and L = 89.0mH . During the oscillations the maximum current in the inductor is 0.846mA .

Part A

What is the maximum charge on the capacitor?

Qmax=   C

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Part B

What is the magnitude of the charge on the capacitor at an instant when the current in the inductor has magnitude 0.496mA ?

q=   C

Explanation / Answer

A)

Here ,

0.5 Qmax^2/C = 0.5 *L*Imax^2

Qmax^2/(3.18 *10^-6) = 0.089 * (0.846*10^-3)^2

Qmax = 4.5 *10^-7 C

the maximum charge on the capacitor is 4.5 *10^-7 C

B)

0.5 L*Imax^2 = 0.5 * Q^2/C +0.5 Li^2

0.089 * (0.846*10^-3)^2 = Q^2/(3.18 *10^-6) + 0.089 * (.496 *10^-3)^2

solving for Q

Q = 3.64 *10^-7 C

the charge on capacitor is 3.64 *10^-7 C