Exercise 30.38 In an L - C circuit, C = 3.18 ? F and L = 89.0mH . During the osc
ID: 1378605 • Letter: E
Question
Exercise 30.38
In an L-C circuit, C = 3.18?F and L = 89.0mH . During the oscillations the maximum current in the inductor is 0.846mA .
Part A
What is the maximum charge on the capacitor?
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Part B
What is the magnitude of the charge on the capacitor at an instant when the current in the inductor has magnitude 0.496mA ?
Exercise 30.38
In an L-C circuit, C = 3.18?F and L = 89.0mH . During the oscillations the maximum current in the inductor is 0.846mA .
Part A
What is the maximum charge on the capacitor?
Qmax= CSubmitMy AnswersGive Up
Part B
What is the magnitude of the charge on the capacitor at an instant when the current in the inductor has magnitude 0.496mA ?
q= CExplanation / Answer
A)
Here ,
0.5 Qmax^2/C = 0.5 *L*Imax^2
Qmax^2/(3.18 *10^-6) = 0.089 * (0.846*10^-3)^2
Qmax = 4.5 *10^-7 C
the maximum charge on the capacitor is 4.5 *10^-7 C
B)
0.5 L*Imax^2 = 0.5 * Q^2/C +0.5 Li^2
0.089 * (0.846*10^-3)^2 = Q^2/(3.18 *10^-6) + 0.089 * (.496 *10^-3)^2
solving for Q
Q = 3.64 *10^-7 C
the charge on capacitor is 3.64 *10^-7 C
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