Problem 32.4 Part A An electron moves along the z-axis with v, = 3.8 × 107 m/s.

Question

Problem 32.4 Part A An electron moves along the z-axis with v, = 3.8 × 107 m/s. As it passes the origin, what are the strength and direction of the magnetic field at the following (z, y, z) positions? (2 cm, 0 cm, 0 cm Express your answers using two significant figures.Enter your answers numerically separated by commas. BBy B,1.91. 10 ,0,0 Submit My Answers Give Up Incorrect; Try Again; 4 attempts remaining Part B (0 cm, 0 cm, 2 cm) Express your answers using two significant figures. Enter your answers numerically separated by commas. B By, B.-o,0,0 T Submit My Answers Give Up Correct Part C O cm, 2 em, 2 cm) Express your answers using two significant figures. Enter your answers numerically separated by commas

Explanation / Answer

part A

distance r = sqrt(2^2+0^2+0^2) = 2cm = 0.02 m

v = 3.8*10^7 k   m/s

position vector r = 0.02i m

q = -1.9*10^-19 C

B = 4*pi*10^-7*-1.6*10^-19*(3.8*10^7 k x 0.02i )/0.02^3

B = -4*pi*10^-7*1.6*10^-19*3.8*10^7*0.02/0.02^3 (-j)

B = 1.91*10^-14 T j

Bx By Bz = 0 , 1.91*10^-14 , 0

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part B

distance r = sqrt(0^2+0^2+2^2) = 2cm = 0.02 m

v = 3.8*10^-7 k m/s

position vector r = 0.02k m

q = -1.9*10^-19 C

B = 4*pi*10^-7*-1.6*10^-19*(3.8*10^7 k x 0.02k )/0.02^3

B = 0

Bx By Bz = 0 , 0 , 0

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distance r = sqrt(0^2+2^2+0^2) = 2.83cm = 0.0283 m

v = 3.8*10^-7 k m/s

position vector r = 0.02j + 0.02 k m

q = -1.9*10^-19 C

B = 4*pi*10^-7*-1.6*10^-19*(3.8*10^7 k x (0.02j + 0.02 k) )/0.02^3

B = -4*pi*10^-7*19*10^-19*3.8*10^-7*0.02/0.02^3 (-i)

B = 1.91*10^-14 T i

Bx By Bz = 1.91*10^-14 ,0 , 0

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