4. Shoaib Aktar of Pakistan set the record for the fastest bowler in the game wi
ID: 1785170 • Letter: 4
Question
4. Shoaib Aktar of Pakistan set the record for the fastest bowler in the game with velocity is vo = 44.8 m/s at a elevation angle = 23.55°. of cricket. Aktar threw a cricket ball a) Calculate the x-component and the y-component of the initial velocity of the cricket ball. b) Calculate R, the range of the cricket ball c) Calculate t, time of flight of the cricket ball. d) Calculate h, the maximum altitude of the cricket ball after Aktar threw it. e) If Aktar had thrown the cricket ball at an elevation angle = 14.6. calculate its range R.Explanation / Answer
v = 44.8 m/s
angle = 23.55
A)
vx = 44.8cos(23.55) = 41.07
vy = 44.8sin(23.55) = 17.9
B)
R = v^2sin(2*theta)/g = 44.8^2*sin(2*23.55)/9.8 = 150 m
C)
t = 2vsin(theta)/g
t = 2*44.8*sin(23.55)/9.8
t = 3.65 sec
D)
H = (vsin(theta))^2/(2g)
H = (44.8*sin(23.55))^2/(2*9.8)
F = 16.35
E)
R = v^2sin(2*theta)/g
R = 44.8^2*sin(2*14.61)/9.8
R = 99.97 m
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