4. Run the following program with the three test values (20.05, 30.65, 40.50) Wh

Question

4. Run the following program with the three test values (20.05, 30.65, 40.50) Why do we need '(int)' in front of longSal in the switch statement? import java.util.scanne r; public class SwitchCastTest [ public static void main (String[] args) i // Create a Scanner named input Scanner input - new Scanner (System.in); // Create a double that will store the input double salary0.00; // Read in salary, use these test values in successive runs: 20.05, 30.65, 40.50 salary - input.nextDouble () long longSal - Math.round (salary); system. out . println("salary = " + salary) ; System. out.println ("longSal - " + longSal); // Use the switch statement to print appropriate message for the salary entered switch ((int)longSal) case 20: System.out.println ("Salary is about $20/hour."); case 30: System.out.println ("Salary is about $30/hour."); case 31: System.out.println ("Salary is about $31/hour."); case 40: System.out.println ("Salary is about $40/hour. ") case 41: System.out.println ("Salary is about $41/hour. "); default: System. out.println ("Salary is out of range."); break; break; break; break; break; break; input.close // Close the scanner object

Explanation / Answer

switch only accepts char, byte, short, int, String or an enum. switch does not accept a long. so, we can cast/convert it to an int so that switch statement accepts it. That's why you see a (int) front of longSal.

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