04: semi-elastic Two hovercraft are on a collision course. They both have the sa

Question

04: semi-elastic Two hovercraft are on a collision course. They both have the same mass (m) and they are approaching the crash point at speeds of 1.0m/s and 2.0m/s respectively. They bump and rebound. The 1t hovercraft has a post-crash speed of 1.5m/s directed away from the crash (to the left). What is the final velocity of the see 1.0m/s 1.5m/s before after 2.0m/s ???? Q5: Inelastic A comet of mass 3.10x10'kg and velocity +501m/s ploughs into a stationary asteroid of mass 7.95x10'kg where it buries itself in the cratered surface. What is the velocity of the asteroid/comet combination after the incident?

Explanation / Answer

Concept : Momentum is conserved in all types of collisions.

1) Taking right side +ve, Initial momentum of two masses = 1*m - 2*m = - m
Momentum of masses, after collision = -1.5m + mV ( where V is velocity of right side mass)
= m( V-1.5)

Equating the two we get
-m= m(V-1.5)
V = 0.5 m/s ( +ve result tells, it is going to right)

2)Momentum of Comet = 3.1x103 x 501 = 1.55x106 kg m/sec
Momentum of Asteroid is zero before collision.
If velocity of combined mass after collision = V, it's momentum = (3.1x103 + 7.95x104) V
equaating initial and final momentum we get
1.55x106 = (3.1x103 + 7.95x104) V
V = 6.3 m/s

Related Questions

Navigate

• Browse (All)
• Browse
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.