0350 L of 0.490 M H2so4 is mixed with o 300 l of 0230 MKoH 17 LAU: red HW 12 5/8

Question

0350 L of 0.490 M H2so4 is mixed with o 300 l of 0230 MKoH 17 LAU: red HW 12 5/8/2017 11:00 PM 6.5/10 Point calaulator Periodic Table Question 8 of 10 Sapling Learning Write the balanced neutralization reaction between H2SO and KOH in aqueous solution. Phases are optional. 0.750 Lof 0.420 M H2SO is mixed with 0.700 L of 0.220 M KOH. What ooncentration of sulfuric acid remains after neutralization? M H,SO There is additional feedback bottom divider bar. bar again to hide the addtional feedback O Previous ® Give Up & View solution Try,Again o Neat HExit

Explanation / Answer

H2SO4 + 2KOH K2SO4 + 2H2O

(0.750 L) * ( 0.420 M ) = 0.315 mol H2SO4

( 0.700 L ) * ( 0.220 M ) = 0.154 mol KOH

0.154 mole of KOH would react completely with 0.154 * (1/2) = 0.077 mol H2SO4 but there is more H2SO4 present than that so H2SO4 is excess and KOH is the limiting reactant

( 0.315 mol H2SO4 initially) - ( 0.077 mol H2SO4 reacted) = 0.238 mol H2SO4 left over

supposing the volumes to be additive ;

( 0.238 mol H2SO4) / ( 0.750 L + 0.700 L) = 0.164 M H2SO4

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