Little help The Expen TAH Ording Autoreed Problem. 5: Consider the three resisto

Question

Little help The Expen TAH Ording Autoreed Problem. 5: Consider the three resistors R,-"Q,R,-36 , and R,-83an the configuration shown in the figure. A potential damerece r-2.5 Vis applied between A and B R3 Cthcespertta.com Part (a) Express the equivalent resistance Re of the combination of Ry and Ry in terms of Ry and R Expression Select from the variables below to write your expression. Note that all variables may not be roquired , sv, sv," o, d, g, h, I, m, R, R1, R2, R, t Part (b) Express the total resistance R off the combination of all three resistors in terms of R, R2 and R Expression R- Select from the variables below to write your expression. Note that all variables may not be required a, B.AV.AV2.,d, g, h. I, m, R, Ri. Rz. R.t Part (c) Calculate the numerical value of the total resistance R in Numerie A numeric value is expected and not an expression. Part (d) Express the current 1 on R, in terms of the potential difference V between A and B and the equivalent resistance R. Expression Select from the variables below to write your expression. Note that all variables may not be required Part (e) Caleulate the numerical value of I in A. Numerie :A numeric value is expected and not an expression. in terms of ar, I, and RJ. Part (f) Express the voltage across R> Expression Select from the variables below to write your expression. Note that all variables may sot be required , p,AV, AV2, "" d, g, h, I, m, R. R., R2, Rs. t Part (g) Express the current 1, through Ry in terms of 4V and Ry Expression Sclect from the variables below to write your expression. Note that all variables may not be required. Part (h) Calculate the numerical value of I2 in A Numeric : A numeric value is expected and not an expression Part (0) Caleulate the numerical value of lg through R Numeric :A numeric value is expected and not an expression

Explanation / Answer

Problem 5) Given,

R1 = 17 ; R2 = 36 ; R3 = 83

a)1/R23 = 1/R2 + 1/R3

R23 = R3 x R2/(R3 + R2)

b)Req = R1 + R23

Req = R1 + R2 R3/(R2 + R3)

c)R23= 83 x 36/(83 + 36) = 25.11

Req = R1 + R23 = 17 + 25.11 = 42.11 Ohm

Hence, Req = 42.11 Ohm

d)I = delta-V/Req

I = delta-V/[ R1 + R2 R3/(R2 + R3)]

e)I = 2.5/42.11 = 0.06 A

Hence, I = 0.06 A

f)V1 = IR1

delta V2 = delta V - V1

delta V2 = delta V - I R1

g)I2 = delta V2/R2

h)delta V2 = 2.5 - 0.06 x 17 = 1.48 A

I2 = 1.48/36 = 0.04 A

Hence, I2 = 0.04 A

i)I3 = 0.06 - 0.04 = 0.02 A

Hence, I3 = 0.02 A

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