Lithium nitride reacts with water to produce ammonia and lithium hydroxide accor

Question

Lithium nitride reacts with water to produce ammonia and lithium hydroxide according to the equation,

Li3N(s) +3H2O(l) --> NH3(g) + 3LiOH(aq)

Heavy water is water with the isotope deuterium in place of ordinary hydrogen, and its formula is D2O. The above reaction can be used to produce heavy ammonia, ND3(g), according to the equation,

Li3N(s) + #D2O(l) --> ND3(g) +3LiOD(aq)

Calculate how many grams of heavy water are required to produce 300.0 mg of ND3(g). The mass of deuterium, D, is 2.014 g/mol.

Explanation / Answer

First we convert the 300 mg of ND3 to moles:

0.3 grams * (1 mol / 18 g) = 0.016667 moles

Stoichiometric relation is 1 mol of ND3 is produced from 3 moles of D2O, so we need 0.05 moles of D2O, which in grams will be:

0.05 moles of D2O * (20 g / mol) = 1 gram of D2O

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