To suck lemonade of density 1030 kg/m3 up a straw to a maximum height of 4.83 cm

Question

To suck lemonade of density 1030 kg/m3 up a straw to a maximum height of 4.83 cm, what minimum gauge pressure (in atmospheres) must you produce in your lungs?
the tolerance is +/-2%

To suck lemonade of density 1030 kg/m3 up a straw to a maximum height of 4.83 cm, what minimum gauge pressure (in atmospheres) must you produce in your lungs?
the tolerance is +/-2%

To suck lemonade of density 1030 kg/m3 up a straw to a maximum height of 4.83 cm, what minimum gauge pressure (in atmospheres) must you produce in your lungs?
the tolerance is +/-2%
the tolerance is +/-2%

Explanation / Answer

rho = 1030 kg/m^3

g = 9.8 m/s^2

h = 4.83 cm = 0.0483 m

usE:

P = rho*g*h

= 1030 kg/m^3 * 9.8 m/s^2 * 0.0483 m

= 487.5 N/m^2

= 487.5 Pa

= 487.5/101325 atm ( because 1 atm = 101325 Pa)

= 4.81*10^-3 atm

Answer: 4.81*10^-3 atm

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