A hydraulic lft with a rectangular platform of length 1.66 m and width 0.63 is u

Question

A hydraulic lft with a rectangular platform of length 1.66 m and width 0.63 is used to raise cars above the ground. The cross-sectional area of luid-filled tube connected to the lift-platform is 0.05 m2. If a car with mass m-500 kg is to be held at position as shown in the figure so that the difference in levels is h-0.12 m, what force F should be exerted on the left?(The atmospheric pressure is P0-1.013×105 Pa. The is 800 kg/m3. The accelaration due to gravity is g-9.80 m/s2 Give your answer in units of Newtons. density of the hydraulic olused QUESTION 11 10 points Save Answer

Explanation / Answer

Pressure at the level of the car = mg/A1 + Patm

Pressure at same level in narrow tube

= F/A2 + rho g h+Patm

Pressure at sane level is equal, so,

F/A2 + rho g h +Patm = mg/A1 +Patm

F = (mg/A1 - rho g h) *A2

= (500*9.8/(0.63*1.66) - 800*9.8*0.12)*0.05

= 187.2 N answer

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