A hungry 70 kg bear walks out on a beam in order to get at some food that in sus

Question

A hungry 70 kg bear walks out on a beam in order to get at some food that in suspended as shown. The beam is uniform has a mass of 20 kg and is 6 m long. The sack of food has a mass of 10 kg. Draw the free body diagram showing all forces prevent. Identify your choice for the axis of rotation, and describe which forces produce the clockwise torque and which ones produce the counterclockwise torque. When the bear is at a distance x = 1.0 m away from the support, what is the tension in the wire? If the wire can withstand a tension of 1000 N, can the bear reach the food safely? Show all your work to determine this answer on an additional sheet of paper.

Explanation / Answer

let the pivot point be axis of rotation. clock wise. mass of the bear, mass of the beam, mass of food. counter clock wise. tension of string. ----------------- we have that x=1. so. 70*g*1+20*g*3+10*g*6=T*6*sin60. so T=360(N). --------------------------- at x=6 T=1020(N). so it is not safe.

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