A hungry 625 -N bear walks out on a beam in an attempt to retrieve some \"goodie

Question

A hungry 625 -N bear walks out on a beam in an attempt to retrieve some "goodies" hanging at the end (Fig. P8.20). The beam is uniform, weighs 230 N, and is 5.00-m long; the goodies weigh 110 N.

(b) When the bear is at x = 1.00 m, find the tension in the wire and the components of the reaction force at the hinge (left side of beam).(Tension, horizontal force on hinge, vertical force on hinge)
404.15 N 202.07 N 615.00 N

(c) If the wire can withstand a maximum tension of 687.0 N, what is the maximum distance the bear can walk before the wire breaks?

Find me part C Please

A hungry 625 -N bear walks out on a beam in an attempt to retrieve some ''goodies'' hanging at the end (Fig. P8.20). The beam is uniform, weighs 230 N, and is 5.00-m long; the goodies weigh 110 N. (b) When the bear is at x = 1.00 m, find the tension in the wire and the components of the reaction force at the hinge (left side of beam).(Tension, horizontal force on hinge, vertical force on hinge) 404.15 N 202.07 N 615.00 N (c) If the wire can withstand a maximum tension of 687.0 N, what is the maximum distance the bear can walk before the wire breaks? Find me part C Please

Explanation / Answer

for part C.

To find the distance, sum the moments about the hinge again:

625N*Xm+250N*2.5m+110 N*5 m -(687sin60)N*5m=0

625*X=-1799.7972

x= 1799.7972/625

X=2.879m

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