HW3-3 A fighter jet is on an mission to bomb a target located at the origin of t
ID: 1777437 • Letter: H
Question
HW3-3 A fighter jet is on an mission to bomb a target located at the origin of the coordinate system shown in figure. At t 0, the pilot find the target and the coordinate of the jet is (-LL), where L=H-2000m, and the jet is flying downward at an angle (8-370) with a constant speed v,(v, 100 m/s), (A)lf the pilot is to keep the velocity unchanged, find the time when pilot should release the bomb so that it will hit the target. (B) if at 0, the target starts moving in the tx-direction with constant speed of TVT 5 m/sec), then determine the time t, for the bomb to hit the target. (The gravitation acceleration g = 10 m/s2 , 1012 3.2) 1,Explanation / Answer
along horizontal
before releasing the bomb
x1 = 100*cos37*t1
after releasing the bomb
x2 = 100*cos37*t2
x1 + x2 = 2000
2000 = 100*cos37*(t1+t2)....(1)
along vertical
before releasing
-y1 = -100*sin37*t1
after releasing
-y2 = -100*sin37*t2 - (1/2)*10*t2^2
y1 + y2 = 2000 =
-2000 = -100*sin37*t1-100*sin37*t2 - 5*t2^2........(1)
solving 1 & 2
t1 = 15.1 s <<<<<------ANSWER
===========================
part B
along horizontal
before releasing the bomb
x1 = 100*cos37*t1
after releasing the bomb
x2 = 100*cos37*t2
for target
x3 = vT*(t1+t2) = 5*(t1+t2)
x1 + x2 = 2000 + x3
2000 = (100*cos37 + 5)*(t1+t2) ....(1)
along vertical
before releasing
-y1 = -100*sin37*t1
after releasing
-y2 = -100*sin37*t2 - (1/2)*10*t2^2
y1 + y2 = 2000 =
-2000 = -100*sin37*t1-100*sin37*t2 - 5*t2^2........(1)
solving 1 & 2
t1 = 12.8 s
t2 = 10.8 s
time taken to hit the target = t1 + t2 = 23.6 s <<<---ANSWER
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