Item 1 Part A Evaluate the magnitude of the cross product A × B (Figure 1) Expre

Question

Item 1 Part A Evaluate the magnitude of the cross product A × B (Figure 1) Express your answer using two significant figures Submit My Answers Give Up Part B Choose the correct direction of the cross product A × B It is zero vecor It is opposite to the direction of A Into the page Out of the page It is opposite to the direction of B Figure 1 of 1 (a) AA 4 6 90° Submit My Answers Give Up 45° Part C Evaluate the magnitude of the cross product C × D Express your answer using two significant figures

Explanation / Answer

Solution) Part A) We have cross product A×B=ABsin(theeta)

Here A=6 , B=5 ,theeta=45

On substituting we get A×B=6.5.sin(45)

A×B=21.21

PART b) direction of cross product A×B can be obtained by using RIGHT HAND RULE . Using this RULE we get the direction into the page.

PART c) we have cross product C×D=CDsin(theeta)

C×D=6.4sin(90)

C×D=24

Part d) direction of cross product of C×D is given by RIGHT HAND RULE . Using this RULE we can determine the direction is out of page .

  

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