Item 1 Part B A student bikes to school by traveling first dN = 0.900miles north

Question

Item 1 Part B A student bikes to school by traveling first dN = 0.900miles north, then dw 0.500miles west, and finally d O.200miles south. Part B You will now find the same quantity algebraically, without the need to use much geometry. Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking. Let d vector N be the displacement vector corresponding to the first leg of the student?s trip, Express d vector N in component form. Express your answer as two numbers separated by a comma (e.g., 1.0,2. 0). By convention, the x component is written first.

Explanation / Answer

here, dN = 0.9 miles , dW = 0.5 miles , dS = 0.2 miles

dN = ( 0.9 - 0.2) j - 0.5 i

dN = -0.5 i -0.7 j

therefore ,

dNx , dNy = (-0.5 , -0.7) miles

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