4. Suppose three resistors were arranged as follows: a 67 Ohm resistor in series

Question

4. Suppose three resistors were arranged as follows: a 67 Ohm resistor in series with two resistors wired in parallel, a 100 Ohm resistor and a 50 Ohm resistor. The resistors are attached to a 12 Volt battery and a current flows out of the battery and through the resistor network.

a) Find the net resistance of the series parallel combination in Ohms.

b) Find the current drawn from the battery in amps.

c) What is the voltage across each resistor?

d) What is the current through each resistor.

e) Check that Kirchoff’s voltage law holds for the circuit.

f) Check that Kirchoff’s current law holds at the junctions in the circuit.

Explanation / Answer

Net resistnace = 67 + 100*50/150 = 100.33 ohm (ans)

Current = V/R = 12/100.33 = 0.12 A (ans)

Volatage across 67 ohm = 0.12*67 = 8.04 V

current across 50 ohm = 0.12*100/150 = 0.08 A

current across 100 ohm = 0.04 A

So Voltage across, 50 ohm = 4 V

Voltage across, 100 ohm = 4 V

current across 50 ohm = 0.12*100/150 = 0.08 A

current across 100 ohm = 0.04 A

current across 67 ohm = 0.12 A

Kirchoff's voltage and current law holds for the circuit

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