A travelling wave has the following expression, in SI units (distance in m, time

Question

A travelling wave has the following expression, in SI units (distance in m, time in s): 15 Volt (z, t) Sin [2 (3.84 × 1014 s-1) m s-1 Find out the following (a-f) a) Amplitude b) Frequency c) Wavelength d) Phase velocity e) Time period f) Direction of propagation. g) If this wave enters a material of refractive index 1.5, what would the wavelength and frequency in that medium be? What would be the phase difference between two points spaced 100 microns apart from each other in the medium of refractive index 1.5? h)

Explanation / Answer

(A) A = 15 V/m

y = 15 V/m sin(2.56 pi x 10^6 z +7.68pi x 10^14 t )

y = A sin(kz + w t)

(B) f = w / 2pi = 3.84 x 10^14 Hz

(C) lambda = 2 pi / k =781.2 x 10^-9 m Or 781.2 nm

(D) v = w / k = 3 x 10^8 m/s

(E) T = 1/f = 2.60 x 10^-15 sec

(f) along -ve z axis

(g) f = 3.84 x 10^14 Hz (it will not change)

wavelength - 781.2 /1.5 = 520.8 nm

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