-1 points 05uriPhys1 10.7P.003 A block of mass 2 kg slides down an inclined plan

Question

-1 points 05uriPhys1 10.7P.003 A block of mass 2 kg slides down an inclined plane at an angle of 45° with a massless tether attached to a pulley with mass 4 kg and radius 0.6 m at the top of the incline (see the following figure). The pulley can be approximated as a disk. The coemicient of kinetic friction on the plane is 0.6. What is the acceleration of the block (in m/s2)? (Enter the magnitude.) My Notes Ask Your 45 m/s2 Additional Materials eBock Submit Answer Save Progress Practice Another Version

Explanation / Answer

on pulley:

R T = ( M R^2 / 2) (a / R )

T = 2 a .... (i)

On mass: 2 g sin45 - f - T = 2 a

f = 0.6 (2 g cos45)

2 g sin45 - 1.2 g cos45 - 2 a = 2 a

a = 1.39 m/s^2

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