3. A 20 Kg box, initially at rest, is pushed for 2 meters with a force of 50 New

Question

3. A 20 Kg box, initially at rest, is pushed for 2 meters with a force of 50 Newtons. If the frictional force is 30 Newtons, what is the kinetic energy of the box at the end of the 2 meters? Note: this is not a machines problem A see-saw (or a lever) for a playground is 10 meters long. The fulcrum, or pivot point, is placed 2 meters from one end and 8 meters from the other end. What is the mechanical advantage of the see-saw? If 800 Newton weight is placed at the short end of the see- saw, what force must be applied to the 8 meter end to keep the weight from falling? 4.

Explanation / Answer

3) work done by all forces = change in KE

50*2 - 30*2 = KE - 0

KE = 40 J answer

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