3. 214 points | Previous Answers SerCP10 6.P.027.W My Notes Ask Your Teach A 68.

Question

3. 214 points | Previous Answers SerCP10 6.P.027.W My Notes Ask Your Teach A 68.0-kg person throws a 0.0410-kg snowball forward with a ground speed of 34.5 m/s. A second person, with a mass of 59.5 kg, catches the snowball. Both people are on skates. The first person is initially moving forward with a speed of 4.00 m/s, and the second person is initially at rest. What are the velocities of the two people after the snowball is exchanged? Disregard the friction between the skates and the ice. (Take the direction the snowball is thrown to be the positive direction. Indicate the direction with the sign of your answer.) m/s (Give your answer to at least three decimal places.) m/s thrower 0.0208 x catcher 0.0238

Explanation / Answer

Use conservation of momentum to solve this problem:

Thrower:

(68 + 0.041) * 4 = 68 V + 0.041*34.5

68.041 4 = 68 V + 1.4145

V = 3.9816 m/s

Catcher:

0.041 34.5 + 59.5 0 = (59.5 + 0.041) V

1.4145 = 59.541 V

V = 0.02376 m/s

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