The rain-soaked shoes of a person may explodeif ground current from nearby light

Question

The rain-soaked shoes of a person may explodeif ground current from nearby lightning vaporizes the water. Thesudden conversion of water to water vapor causes a dramaticexpansion that can rip apart shoes. Water has density 1000kg/m3 and requires 2256 kJ/kg to be vaporized. Ifhorizontal current lasts 2.00 ms and encounters water withresistivity 145 ohm·m, length 12.0 cm, and verticalcross-sectional area 1.5 x 10-4m2, what average current is required to vaporize thewater? I just wasn't sure how to piece the problemtogether. The rain-soaked shoes of a person may explodeif ground current from nearby lightning vaporizes the water. Thesudden conversion of water to water vapor causes a dramaticexpansion that can rip apart shoes. Water has density 1000kg/m3 and requires 2256 kJ/kg to be vaporized. Ifhorizontal current lasts 2.00 ms and encounters water withresistivity 145 ohm·m, length 12.0 cm, and verticalcross-sectional area 1.5 x 10-4m2, what average current is required to vaporize thewater? I just wasn't sure how to piece the problemtogether. The rain-soaked shoes of a person may explodeif ground current from nearby lightning vaporizes the water. Thesudden conversion of water to water vapor causes a dramaticexpansion that can rip apart shoes. Water has density 1000kg/m3 and requires 2256 kJ/kg to be vaporized. Ifhorizontal current lasts 2.00 ms and encounters water withresistivity 145 ohm·m, length 12.0 cm, and verticalcross-sectional area 1.5 x 10-4m2, what average current is required to vaporize thewater? I just wasn't sure how to piece the problemtogether. The rain-soaked shoes of a person may explodeif ground current from nearby lightning vaporizes the water. Thesudden conversion of water to water vapor causes a dramaticexpansion that can rip apart shoes. Water has density 1000kg/m3 and requires 2256 kJ/kg to be vaporized. Ifhorizontal current lasts 2.00 ms and encounters water withresistivity 145 ohm·m, length 12.0 cm, and verticalcross-sectional area 1.5 x 10-4m2, what average current is required to vaporize thewater? I just wasn't sure how to piece the problemtogether. The rain-soaked shoes of a person may explodeif ground current from nearby lightning vaporizes the water. Thesudden conversion of water to water vapor causes a dramaticexpansion that can rip apart shoes. Water has density 1000kg/m3 and requires 2256 kJ/kg to be vaporized. Ifhorizontal current lasts 2.00 ms and encounters water withresistivity 145 ohm·m, length 12.0 cm, and verticalcross-sectional area 1.5 x 10-4m2, what average current is required to vaporize thewater? I just wasn't sure how to piece the problemtogether. The rain-soaked shoes of a person may explodeif ground current from nearby lightning vaporizes the water. Thesudden conversion of water to water vapor causes a dramaticexpansion that can rip apart shoes. Water has density 1000kg/m3 and requires 2256 kJ/kg to be vaporized. Ifhorizontal current lasts 2.00 ms and encounters water withresistivity 145 ohm·m, length 12.0 cm, and verticalcross-sectional area 1.5 x 10-4m2, what average current is required to vaporize thewater? I just wasn't sure how to piece the problemtogether.

Explanation / Answer

Find mass of water by using density and volume Find energy necessary to vaporize water Find resistance of water Find power using energy and time Find current using    power =current2 * resistance . mass = density * length * area = 1000 * 0.12 *0.00015 =   0.018 kg . energy = 2256 kJ / kg * 0.018 kg = 40.608 kJ = 40608 Joules .    resistance = resistivity * length /area = 145 * 0.12 / 0.00015 =   116000 ohms .    power = energy / time = 40608 J / 0.002 sec =   20304000 Watts .      power = I2R .       20304000 = I2 *116000 .    I =    13.23 amps

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