A wagon is rolling forward on level ground. Friction isnegligible. The person si

Question

A wagon is rolling forward on level ground. Friction isnegligible. The person sitting on the wagon is holding a rock. Thetotal mass of the wagon, rider, & rock is 95 kd. The mass ofthe rock is 0.3 kg. The person throws the rock with a speed of 16m/s. Both speeds are relative to the ground a) find the speed of the wagon after the rock is throwndirectly forward b) & directly backward A wagon is rolling forward on level ground. Friction isnegligible. The person sitting on the wagon is holding a rock. Thetotal mass of the wagon, rider, & rock is 95 kd. The mass ofthe rock is 0.3 kg. The person throws the rock with a speed of 16m/s. Both speeds are relative to the ground a) find the speed of the wagon after the rock is throwndirectly forward b) & directly backward

Explanation / Answer

Total mass of wagon, rider, & rock , m1 = 95 kg mass of the rock, m2 =0.3 kg initial speed of the wagon, u = 0.5 m/s mass of wagon + rider , m3 = 95 - 0.3 = 94.7 kg final speed of wagon + rider , v = ? According to law of conservation of momentum, total initial momentum = total final momentum (a) speed of the rock, v1 = 16 m/s m1 u = m2 v1 + m3 v 95 * 0.5 = 0.3 * 16 + 94.7 * v v = 0.45 m/s (b) speed of the rock, v1 = -16 m/s ( direction is backward) m1 u = m2 v1 + m3 v 95 * 0.5 = 0.3 * -16 + 94.7 * v v = 0.5 m/s speed of the rock, v1 = -16 m/s ( direction is backward) m1 u = m2 v1 + m3 v 95 * 0.5 = 0.3 * -16 + 94.7 * v v = 0.5 m/s

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