An air puck of mass m 1 is tied to a stringand allowed to revolve in a circle of

Question

An air puck of mass m1 is tied to a stringand allowed to revolve in a circle of radius R on africtionless horizontal table. The other end of the string passesthrough a small hole in the center of the table, and a load of massm2 is tied to the string. The suspended loadremains in equilibrium while the puck on the tabletop revolves.Answer the following questions by writing a formula using m_1 form1, m_2 for m2, g forg (gravity), and R for R as necessary. (a) What is the tension in the string?
T =

(b) What is the radial force acting on the puck?
F =

(c) What is the speed of the puck?
v =


(d) Qualitatively describe what will happen in the motion of thepuck if the value of m2 is somewhat increasedby placing an additional load on it.
4

(e) Qualitatively describe what will happen in the motion of thepuck if the value of m2 is instead decreased byremoving a part of the hanging load.
5 An air puck of mass m1 is tied to a stringand allowed to revolve in a circle of radius R on africtionless horizontal table. The other end of the string passesthrough a small hole in the center of the table, and a load of massm2 is tied to the string. The suspended loadremains in equilibrium while the puck on the tabletop revolves.Answer the following questions by writing a formula using m_1 form1, m_2 for m2, g forg (gravity), and R for R as necessary. (a) What is the tension in the string?
T =

(b) What is the radial force acting on the puck?
F =

(c) What is the speed of the puck?
v =


(d) Qualitatively describe what will happen in the motion of thepuck if the value of m2 is somewhat increasedby placing an additional load on it.
4

(e) Qualitatively describe what will happen in the motion of thepuck if the value of m2 is instead decreased byremoving a part of the hanging load.
5

Explanation / Answer

(a)
   as the m2 mass is in equilibrium thetension in the string will be
   T = m2 g
      = ........ N
(b)
   the tension in the string must produce the centripetalacceleration of the puck so we get
   Fc = T
        = ....... N
(c)
   in this case
   Fc = m1(vt2 / r)
   vt = (r Fc /m1)
       = ........ m / s

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