A 47.0 g golf ball is driven from the tee with an initial speed of54.0 m/s and r

Question

A 47.0 g golf ball is driven from the tee with an initial speed of54.0 m/s and rises to a height of25.0 m. (a) Neglect air resistance and determine thekinetic energy of the ball at its highest point.
1 J

(b) What is its speed when it is 7.0 mbelow its highest point?
2 m/s ssm One kilowatt·hour (kW·h) is the amount ofwork or energy generated when one kilowatt of power is supplied fora time of one hour. A kilowatt·hour is the unit of energyused by power companies when figuring out your electric bill.Determine the number of joules of energy in onekilowatt·hour.
1 J

Section 6.7Power (a) Neglect air resistance and determine thekinetic energy of the ball at its highest point.
1 J

(b) What is its speed when it is 7.0 mbelow its highest point?
2 m/s ssm One kilowatt·hour (kW·h) is the amount ofwork or energy generated when one kilowatt of power is supplied fora time of one hour. A kilowatt·hour is the unit of energyused by power companies when figuring out your electric bill.Determine the number of joules of energy in onekilowatt·hour.
1 J

Section 6.7Power
Section 6.7Power

Explanation / Answer

Mass of ball m = 47.0 g
                       = 0.047 kg
Initial speed v = 54.0 m/s
Height h = 25.0 m. (a)The kinetic energy of the ball at itshighest point V = ? from law of conservation of energy ,Initial K.E = P.E at height h + K.E at height h                                              ( 1/ 2) m v ^ 2 = mgh + ( 1/ 2) m V ^ 2                                                                  V= [ v ^ 2 - 2gh ]                                                                     = 49.25 m / s (b). Speed at a point below 7 m from heighestpoint V ' = [ v ^ 2 - 2g h ' ] where h ' = h - 7 = 25 - 7 = 18 m plug the values weget   V ' = 50.62 m/ s

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