A uniformly accelerated car passes three equally spaced trafficsigns. The signs

Question

A uniformly accelerated car passes three equally spaced trafficsigns. The signs are separated by a distance d =24 m. The car passes the first sign att1 = 1.5 s, the secondsign at t2 = 3.7 s,and the third sign at t3 = 4.7 s.

(a) What is the average velocity of the carduring the time it that it is moving between the first twosigns?
1 m/s

(b) What is the average velocity of the car during the time that itpasses between the second and third signs?
2 m/s

(c) What is the acceleration of the car?
3 m/s^2 (a) What is the average velocity of the carduring the time it that it is moving between the first twosigns?
1 m/s

(b) What is the average velocity of the car during the time that itpasses between the second and third signs?
2 m/s

(c) What is the acceleration of the car?
3 m/s^2

Explanation / Answer

I am sorry about the first question, I misread it, hence my answerwas different. As for part C, it is 6.52 m/s2 . I had abrain fart, as it were. Here is the math s = s0 + v0 * t + (1/2) * a *t2 = 0 + 0 * 4.7 + 0.5 * a * (4.7s)2 Solve for a, and a = 6.52 m/s2

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