A uniform wooden block has sides L , W and H , where L > W > H . An axis passes

Question

A uniform wooden block has sides L, W and H, where L > W > H. An axis passes through this block from the center of one face to the opposite face. Which faces should the axis pass through to get Imax, the largest moment of inertia, and Imin, the minimum moment of inertia?

A. For Imax: use L x W, for Imin: use L x H

B. For Imax: use L x W, for Imin: use W x H    

C. For Imax: use L x H, for Imin: use W x H

D. For Imax: use W x H, for Imin: use L x W

E. For Imax: use L x H, for Imin: use L x W

F. For Imax: use W x H, for Imin: use L x H

Explanation / Answer

moment of inertia of a block about an axis perpendicularly passing through a face= m(a2 +b2)/12, where a and b are face dimension, m is mass

moment of inertia increases as distance of particle from axis increases hence it will be max across l x W and minimum across WxH

so answer will be (b)

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