A swimmer heads directly across a river, swimming at 4.70 m/srelative to still w

Question

A swimmer heads directly across a river, swimming at 4.70 m/srelative to still water. He arrives at a point 71.0 m downstreamfrom the point directly across the river, which is 142.0 mwide.

What is the speed of the river current?
2.35 m/s (t=142m/47m/s)

What is the swimmer's speed relative to the shore?
5.25 m/s (Pythagorean Thm. with the velocityof the swimmer and velocity of the river current.)

In what direction should the swimmer head so as to arrive at thepoint directly opposite his starting point? Express your answer interms of the angle with respect to a line drawn directly across theriver.
??

Explanation / Answer

         Q 3)       velocity of swimmer instill water , V m = 4.7 m/s        from the firstquestion,                                            velocity of river current, V w = 2.35 m/s     Let,                         direction should the swimmer head soas to arrive   at the point directly opposite hisstarting point                   with respect to a line drawn directly across the river be ''           Sin =  V w / Vm = 2.35 / 4.7 = 1/ 2                      = 30 o

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