1.) The position of a person is given by x= 4.0t -0.50t^2where x is in meters an
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Question
1.) The position of a person is given by x= 4.0t -0.50t^2where x is in meters and t is in seconds. what is the averagevelocity between t=0 and t=8.0s? Also between t=8.0s andt=10.0s? 2.) the position of a particle in meters is given by x=2.5t +3.1 t^2 - 4.5t^3, where t is the time in seconds. whar are theinstantaneous velocity and instantaneous acceleration at t= 0.0s?at t= 2.0s? whar are the average velocity and average accelerationfor the time interval 0 greater than or equal to t greater thanequal to 2s ? 1.) The position of a person is given by x= 4.0t -0.50t^2where x is in meters and t is in seconds. what is the averagevelocity between t=0 and t=8.0s? Also between t=8.0s andt=10.0s? 2.) the position of a particle in meters is given by x=2.5t +3.1 t^2 - 4.5t^3, where t is the time in seconds. whar are theinstantaneous velocity and instantaneous acceleration at t= 0.0s?at t= 2.0s? whar are the average velocity and average accelerationfor the time interval 0 greater than or equal to t greater thanequal to 2s ?Explanation / Answer
The displacement of the person is given by x = 4.0t - 0.50t2 The position of the person at t = 0 is x = 0 And the position of the person at t = 8.0s is x = (4.0)(8.0) - (0.50s)(8.0s)2 = 32.0 - 32.0 = 0 Then the average velocity in between t = 0 to t = 8.0s is zero.That means in this time interval it is moving with constantvelocity. The position of the person at t = 10.0s is x = (4.0)(10.0s) - (0.50)(10.0s)2 = 40 - 50 = -10m Now the average velocity in t = 8.0s to t = 10.0s is v = (-10m) / (2s) = -5.0m/s
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