1.) The combustion of a mol of an unidentified carbohydrate yields 6 mol CO2 and

Question

1.) The combustion of a mol of an unidentified carbohydrate yields 6 mol CO2 and 6 mol H2O.
a. How many moles of CO2 can be produced from 60 g of the carbohydrate used in Question 1? b. What would be the molar concentration of a 150 mL solution of that same carbohydrate sample? 1.) The combustion of a mol of an unidentified carbohydrate yields 6 mol CO2 and 6 mol H2O.
a. How many moles of CO2 can be produced from 60 g of the carbohydrate used in Question 1? b. What would be the molar concentration of a 150 mL solution of that same carbohydrate sample?
a. How many moles of CO2 can be produced from 60 g of the carbohydrate used in Question 1? b. What would be the molar concentration of a 150 mL solution of that same carbohydrate sample? a. How many moles of CO2 can be produced from 60 g of the carbohydrate used in Question 1? b. What would be the molar concentration of a 150 mL solution of that same carbohydrate sample?

Explanation / Answer

1)

we know that

carbohydrate have the empirical formula Cm(H20)n

the combustion equation is given by

Cm(H20)n + m02 ---> m C02 + n H20

given

6 mol C02 and 6 mol H20 are produced

so

m = 6 and n = 6

so

the carbohydrate is C6(H20)6 = C6H12O6

now

the molar mass of C6H12O6 = ( 6 x 12) + ( 12 x 1) + ( 6 x 16)

molar mass of C6H1206 = 72 + 12 + 96

molar mass of C6H1206 = 180 g / mol

a)

now

given 60 g of Carbohydrate

we know that

moles = mass / molar mass

so

moles of carbohydrate = 60 / 180 = 1/3

now

C6H1206 + 602 ---> 6C02 + 6 H20

we can see that

moles of C02 produced = 6 x moles of carbohydrate

so

moles of C02 produced = 6 x 1/3

moles of C02 produced = 2

so

2 moles of C02 can be produced from 60 g of carbohydrate

b)

now

we know that

molarity = moles of carbohydrate x 1000 / volume (ml)

given

volume = 150 ml

so

molarity = (1/3) x 1000 / 150

molarity = 2.222

so

the molar concentration of the solution is 2.222 M

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.