A woman of mass 75 kg is at rest. She starts running with anacceleration of 2 m/

Question

A woman of mass 75 kg is at rest. She starts running with anacceleration of 2 m/s2 tangential to the edge of astationary merry-go-round.After running for 6 secs, she jumps onthe merry-go-round, setting it into motion. Themerry-go-round has a radius of 2m and a moment of inertia about anaxis through its center of 1200 kg m2 . What is theangular velocity of the system after the woman has jumped on? What is the kinetic energy of the system after the woman walks tothe center of the merry-go-round?

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Explanation / Answer

               Given that the mass of woman is m = 75 kg                 accelarationis a = 2 m/s2                     Time taken is t = 6 sec                radius of the disk si r = 2 m                moment of inertia is I = 1200kg.m2     ------------------------------------------------------------------------------------      The final veloctiy of woman is V = u + at                                                         =0 + at                                                         =2 m/s2 *6sec                                                              = 12 m/s      From the conservationof angular momnetum                              mVr = ( I +mr2 )                                   = mVr / ( I +mr2 )                                       =---------- rad/s   

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