PLEASE ANSWER SIMPLY, EXPLAINING WHY YOU DID WHAT YOUDID. LIST ANY FORMULA USED

Question

PLEASE ANSWER SIMPLY, EXPLAINING WHY YOU DID WHAT YOUDID. LIST ANY FORMULA USED WITH THE VARIABLE LISTED EXPLICITLY NEXTTO IT. PLEASE ANSWER APPROPRIATELY; I WILL RATE ACCORDINGLY. THANK YOU. Monochromatic light of wavelength653nm falls on a slit. If theangle between the first bright fringes on either side of thecentral maximum is 32 degrees, estimate the slit width. Dsin = (m+1/2)LAMBDA BY THE WAY- I BELIEVE THE = 32/2 AND THAT THE TWO"MAX." ORDERS ARE -1 AND 1. PLEASE SHOW ALL CALCULATIONS. THANKS:) PLEASE ANSWER SIMPLY, EXPLAINING WHY YOU DID WHAT YOUDID. LIST ANY FORMULA USED WITH THE VARIABLE LISTED EXPLICITLY NEXTTO IT. PLEASE ANSWER APPROPRIATELY; I WILL RATE ACCORDINGLY. THANK YOU. Monochromatic light of wavelength653nm falls on a slit. If theangle between the first bright fringes on either side of thecentral maximum is 32 degrees, estimate the slit width. Dsin = (m+1/2)LAMBDA BY THE WAY- I BELIEVE THE = 32/2 AND THAT THE TWO"MAX." ORDERS ARE -1 AND 1. PLEASE SHOW ALL CALCULATIONS. THANKS:)

Explanation / Answer

Given :                Wave length ( )   = 632 x 10-9    m                Angle ( )   = 32 degree                Order of the fringe = 1 In single slit diffraction ,                  Condition for Maxima is :                           D sin     =    (m + 1 /2 )                or       D sin32    =   ( 1 + 1 / 2) *   632 x 10-9    m                or       D sin32    =    9.48 x 10-7                  or           D         =   ( 9.48 x 10-7 ) / sin32                                           =   1.78   x 10-6  m                                           =   1.78   m Hope this helps u!

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.