PLEASE ANSWER IN STEP BY STEP AND FOR THE FORMULAS PLEASE POST THEM AS IMAGES 1.

Question

PLEASE ANSWER IN STEP BY STEP AND FOR THE FORMULAS PLEASE POST THEM AS IMAGES  

1.    Molybdenum has a BCC crystal structure and has an atomic radius of 0.1363 nm.  Calculate its packaging factor.

2.    Problems:  

3.9:

Calculate the radius of a tantalum (Ta) atom, given that Pd has an FCC crystal structure, a density of 12.0 g/cm^3, and an atomic weight 106.4 g/mol

3.11

A hypothetical metal has the simple cubic crystal structure, if its atomic weight is 75.5 g/mol and the atomic radius is 0.145 nm, compute its density.

3.16

The atomic weight, density, and atomic radius for three hypothetical alloys are listed in the fol-lowing table. For each, determine whether its crystal structure is FCC, BCC, or simple cubic and then justify your determination.

Explanation / Answer

3.9volume = mass/density = (106.4g/mol)/12g/cm3 = 8.8667cm3/mol = 8.8667/6.022 x 10^23 = 1.4724 x 10^-23cm3/atom. Since the structure is cubic, then radius = length of the side of the cube = cube root of 1.4724 x 10^-23cm3 = 2.45 x 10^-8cm = 2.45 x 10^-10m

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