The gymnast shown in the figure is performing a backwards giantswing on the high
ID: 1755551 • Letter: T
Question
The gymnast shown in the figure is performing a backwards giantswing on the high bar. Starting from rest in a near-verticalorientation, he rotates around the bar in a counterclockwisedirection, keeping his body and arms straight. Friction between thebar and the gymnast's hands exerts a constant torque opposing therotational motion. If the angular velocity of the gymnast atposition 2 is measured to be 3.75 rad/s,determine his angular velocity at position 3. (Note that thismaneuver is called a backwards giant swing, even though the motionof the gymnast would seem to be forwards.)1 rad/s
Explanation / Answer
let us take that the angular velocity as4.75 rad / swe know that
w22 -w12 = 2
or = (w22 -w12/2) w2 = 4.75 rad/s,w1 = 0and = (/2) radian = (3.14/2) radian = 1.57radian or = ((4.75)2 -(0)2/2 * 1.57) = 7.2 rad/s2 let the angular velocity of the gymnast atposition 3 be w3 therefore w32 -w22 = 21 or w32 =w22 + 21 or w3 =[w22 +21]1/2 1 = (/2) radian =(3.14/2) radian = 1.57 radian or w3 = [(4.75)2 + 2 *7.2 * 1.57]1/2 or w3 = 6.72 rad/s 1 = (/2) radian =(3.14/2) radian = 1.57 radian or w3 = [(4.75)2 + 2 *7.2 * 1.57]1/2 or w3 = 6.72 rad/s
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