A car traveling at 20 m/s turns a corner with a turn-radius of60 meters. What is

Question

A car traveling at 20 m/s turns a corner with a turn-radius of60 meters. What is the magnitude of the car's acceleration duringthe turn, in m/s2? What is the car's angular velocity, inrad/s?

I need to know the steps required to solve the problem tothree significant figures.

A car traveling at 20 m/s turns a corner with a turn-radius of60 meters. What is the magnitude of the car's acceleration duringthe turn, in m/s2? What is the car's angular velocity, inrad/s?

I need to know the steps required to solve the problem tothree significant figures.

Explanation / Answer

            Given that the iniital velocity is u = 20 m/s             Radius is r = 60 m ----------------------------------------------------------------------------         The accelarationis a = u2 /r                                          =(20m/s)2 / 60m                                          =6.66 m/s2            The angularvelocity is = u /r                                               = 20m/s / 60m                                               = 0.33 rad/s

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