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A car starts from rest and travels for6.0 s with a uniform acceleration of+1.6m/

ID: 1753547 • Letter: A

Question

A car starts from rest and travels for6.0 s with a uniform acceleration of+1.6m/s2. The driver then applies the brakes, causing auniform acceleration of -1.0 m/s2. If the brakes are applied for2.0 s, determine each of thefollowing. (a) How fast is the car going at the end of thebraking period?
1 m/s
(b) How far has it gone?
2 m A car starts from rest and travels for6.0 s with a uniform acceleration of+1.6m/s2. The driver then applies the brakes, causing auniform acceleration of -1.0 m/s2. If the brakes are applied for2.0 s, determine each of thefollowing. (a) How fast is the car going at the end of thebraking period?
1 m/s
(b) How far has it gone?
2 m

Explanation / Answer

GIVEN DATA : initial velocity = v = 0 m/s time taken= t =6 seconds uniform acceleration = a = +1.6 m/s2 uniform deceleration = -1.0 m/s2 brakes are applied for 2.0 sec. final velocity = v' = ? distance covered = s = ? SOLUTION : for time t = 6 sec ,velocity of the car = 0 +(1.6) (6) = 9.6 m/s. hence when brakes are applied then velocity ofcar =9.6 m/s. using equation v' = v + at so required final velocity of car = v'= 9.6+(-1) (2) = 7.6 m/s. using s = vt + 1/2 at2 using s = vt + 1/2 at2 while distance covered = s =(9.6) (2) +(0.5) (-1) (2)2 = 19.2 - 2 = 17.6 meter
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