A 17 g object moving to the right at 32 cm/s overtakes andcollides elastically w

Question

A 17 g object moving to the right at 32 cm/s overtakes andcollides elastically with a 27 g object moving in the samedirection at 13 cm/s. Find the velocity of the slower object afterthe collision. Answer in units of cm/s. b.) Find the velocity of the faster object after thecollision. Answer in units of cm/s. A 17 g object moving to the right at 32 cm/s overtakes andcollides elastically with a 27 g object moving in the samedirection at 13 cm/s. Find the velocity of the slower object afterthe collision. Answer in units of cm/s. b.) Find the velocity of the faster object after thecollision. Answer in units of cm/s.

Explanation / Answer

        Given that themasses are m1 = 17g and m2 = 27 g          Initalspeeds are u1 = 32 cm/s and u2 = 13 cm/s ------------------------------------------------------------------------- Let the masses of the two bodies are m1 and m2
        the initial velocitiesare U1,U2 respectively
        the finalvelocities are V1,V2 respectively. from the law of conservation of momentum             m1*U1+m2*U2 = m1*V1+m2*V2                       m1(U1-V1) = m2*(V2 - U2)    ----------(1)   from the law of conservation of Kineticenergy             (1/2)m1*U12+(1/2)m2*U22 =(1/2)m1*V12+ (1/2)m2*V22            m1(U12-V12) =m2*(V22 - U22)   ----------(2) devide the equation (1) by (2) weget                      U1+V1 = V2 +U2               V1 =V2 + U2  -U1              V2   = U1+V1 -U2            substitude the value of   V2 value in equation (1) we get                         V1 = (m1-m2)*U1/(m1+m2) + (2m2)U2 /(m1+m2)-----------(3)        substitude the valueof   V1 value in equation (1) weget                      V2 = (m2-m1)U2 /(m1+m2) + (2m1)U1 /(m1+m2)                  -----------(4) ----------------------------------------------------------------------------------------------------------        From the equation (3) weget final velocity of the mass m1 is                        V1 = (m1-m2)*U1/(m1+m2) + (2m2)U2 /(m1+m2)                              = ---------- cm/s        From the equation (4) weget final velocity of the mass m2 is                       V2 = (m2-m1)U2 /(m1+m2) + (2m1)U1 /(m1+m2)                              =------------ cm/s Let the masses of the two bodies are m1 and m2
        the initial velocitiesare U1,U2 respectively
        the finalvelocities are V1,V2 respectively. from the law of conservation of momentum             m1*U1+m2*U2 = m1*V1+m2*V2                       m1(U1-V1) = m2*(V2 - U2)    ----------(1)   from the law of conservation of Kineticenergy             (1/2)m1*U12+(1/2)m2*U22 =(1/2)m1*V12+ (1/2)m2*V22            m1(U12-V12) =m2*(V22 - U22)   ----------(2) devide the equation (1) by (2) weget                      U1+V1 = V2 +U2               V1 =V2 + U2  -U1              V2   = U1+V1 -U2            substitude the value of   V2 value in equation (1) we get                         V1 = (m1-m2)*U1/(m1+m2) + (2m2)U2 /(m1+m2)-----------(3)        substitude the valueof   V1 value in equation (1) weget                      V2 = (m2-m1)U2 /(m1+m2) + (2m1)U1 /(m1+m2)                  -----------(4) ----------------------------------------------------------------------------------------------------------        From the equation (3) weget final velocity of the mass m1 is                        V1 = (m1-m2)*U1/(m1+m2) + (2m2)U2 /(m1+m2)                              = ---------- cm/s        From the equation (4) weget final velocity of the mass m2 is                       V2 = (m2-m1)U2 /(m1+m2) + (2m1)U1 /(m1+m2)                              =------------ cm/s            m1(U12-V12) =m2*(V22 - U22)   ----------(2) devide the equation (1) by (2) weget                      U1+V1 = V2 +U2               V1 =V2 + U2  -U1              V2   = U1+V1 -U2            substitude the value of   V2 value in equation (1) we get                         V1 = (m1-m2)*U1/(m1+m2) + (2m2)U2 /(m1+m2)-----------(3)        substitude the valueof   V1 value in equation (1) weget                      V2 = (m2-m1)U2 /(m1+m2) + (2m1)U1 /(m1+m2)                  -----------(4) ----------------------------------------------------------------------------------------------------------        From the equation (3) weget final velocity of the mass m1 is                        V1 = (m1-m2)*U1/(m1+m2) + (2m2)U2 /(m1+m2)                              = ---------- cm/s        From the equation (4) weget final velocity of the mass m2 is                       V2 = (m2-m1)U2 /(m1+m2) + (2m1)U1 /(m1+m2)                              =------------ cm/s      V1 =V2 + U2  -U1              V2   = U1+V1 -U2            substitude the value of   V2 value in equation (1) we get                         V1 = (m1-m2)*U1/(m1+m2) + (2m2)U2 /(m1+m2)-----------(3)        substitude the valueof   V1 value in equation (1) weget                      V2 = (m2-m1)U2 /(m1+m2) + (2m1)U1 /(m1+m2)                  -----------(4) ----------------------------------------------------------------------------------------------------------        From the equation (3) weget final velocity of the mass m1 is                        V1 = (m1-m2)*U1/(m1+m2) + (2m2)U2 /(m1+m2)                              = ---------- cm/s        From the equation (4) weget final velocity of the mass m2 is                       V2 = (m2-m1)U2 /(m1+m2) + (2m1)U1 /(m1+m2)                              =------------ cm/s         V2   = U1+V1 -U2            substitude the value of   V2 value in equation (1) we get                         V1 = (m1-m2)*U1/(m1+m2) + (2m2)U2 /(m1+m2)-----------(3)        substitude the valueof   V1 value in equation (1) weget                      V2 = (m2-m1)U2 /(m1+m2) + (2m1)U1 /(m1+m2)                  -----------(4) ----------------------------------------------------------------------------------------------------------        From the equation (3) weget final velocity of the mass m1 is                        V1 = (m1-m2)*U1/(m1+m2) + (2m2)U2 /(m1+m2)                              = ---------- cm/s        From the equation (4) weget final velocity of the mass m2 is                       V2 = (m2-m1)U2 /(m1+m2) + (2m1)U1 /(m1+m2)                              =------------ cm/s    substitude the value of   V2 value in equation (1) we get                         V1 = (m1-m2)*U1/(m1+m2) + (2m2)U2 /(m1+m2)-----------(3)        substitude the valueof   V1 value in equation (1) weget                      V2 = (m2-m1)U2 /(m1+m2) + (2m1)U1 /(m1+m2)                  -----------(4) ----------------------------------------------------------------------------------------------------------        From the equation (3) weget final velocity of the mass m1 is                        V1 = (m1-m2)*U1/(m1+m2) + (2m2)U2 /(m1+m2)                              = ---------- cm/s        From the equation (4) weget final velocity of the mass m2 is                       V2 = (m2-m1)U2 /(m1+m2) + (2m1)U1 /(m1+m2)                              =------------ cm/s                       V2 = (m2-m1)U2 /(m1+m2) + (2m1)U1 /(m1+m2)                              =------------ cm/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.