A police car going 25 mph spots a speeding car going at 85 mph and200 ft ahead o

Question

A police car going 25 mph spots a speeding car going at 85 mph and200 ft ahead of him. The police car accelerates at 25ft/s2 . The reaction time of the police car is 0.8 sec.How many total seconds will it take the police to reach thespeeding car and how many miles from her starting position will thepolice car have traveled by the time he reaches the speeding carand what is the police car's velocity? Answer the same question, if2 sec after the police accelerates, the speeding car alsoaccelerates at 10 ft/s2 .

Explanation / Answer

              let the distance travelled by the speedicar in time t =S time takne for the speeding car to reach S               t = S / v d = distance travelled v = velocity of the car and the distance travelled by the polive car in atimet-0.8sec = S+200ft                time taken by the police car to travell a distcneS+200ft            S+200ft = v(t-0.8sec) + a(t-0.8)^2 / 2       v = initial velocity ofthe police car       a = accleration of the polivecar       t = time oftravell . from the abv two relations we can solve for S and t .                           

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