With no gene linkage, a cross between parents AaBBCcdd times aaBbCcDd can yield

Question

With no gene linkage, a cross between parents AaBBCcdd times aaBbCcDd can yield how many different genotypes of offspring? 4 9 12 24 32 During what part of cell division does crossing-over/recombination occur? S-phase prophase of meiosis I metaphase of mitosis prophase of meiosis II both (b) and (d) If a man has hemophilia an X-linked recessive disorder, we know for sure that his; Female mate does not have hemophilia Male offspring will have hemophilia Biological father had hemophilia Biological mother was a carrier or had hemophilia Female offspring will have hemophilia At the start of translation, the ribosome binds to: The very 3' end of mRNA The TATA box The promoter The 5' cap The start codon A human XXY and homozygous recessive for the tfm mutation would be: Chromosomally & phenotypically male Chromosomally female; phenotypically male Chromosomally & phenotypically female Chromosomally male; phenotypically female Chromosomally female; phenotypically female and male Which DNA replication enzyme has 3' rightarrow 5' exonuclease activity? DNA Primase DNA polymerase I DNA polymerase III (b) and (c) (a), (b), and (c)

Explanation / Answer

1. The answer is e. 32 (2*2*4*2)
2. The answer is b. Prophase of meiosis I (In pachytene stage of the meiosis I)
3. The answer is d. The start codon.
4. The answer is d. Biological mother was a carrier or had haemophilia (Because the X chromosome is son came from mother only)
5. The answer is d. Chromosomally male and phenotypically female (XXY - Klinefilter syndrome, Aneuploidy of Sex chromomes, due to mutation in tfm they will develop female sex organs)

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