If someone might be able to kindly give me a step-by-stepwalkthrough in order to

Question

If someone might be able to kindly give me a step-by-stepwalkthrough in order to answer this, I would be the happiest personin the world right now!!   :-)   Thank you somuch if you are able to help!!
A 0.150-kg projectile is fired with a velocity of +715 m/s ata 2.00 kg wooden block that rests on a frictionlesstable.   The velocity of the block, immediately after theprojectile passes through it, is +40.0 m/s. Find the velocitywith which the projectile exits from the block. If someone might be able to kindly give me a step-by-stepwalkthrough in order to answer this, I would be the happiest personin the world right now!!   :-)   Thank you somuch if you are able to help!!
A 0.150-kg projectile is fired with a velocity of +715 m/s ata 2.00 kg wooden block that rests on a frictionlesstable.   The velocity of the block, immediately after theprojectile passes through it, is +40.0 m/s. Find the velocitywith which the projectile exits from the block.

Explanation / Answer

according to the law of conservation of momentum we have m1 * u1 + m2 * u2 = m1 * v1 + m2 * v2 -------------(1) m1 = 0.150 kg u1 = +715 m/s m2 = 2.00 kg u2 = 0 v1 = the velocity with which the projectile exits from theblock v2 = +40.0 m/s solving equation (1) for v1 we get v1 = [m1 * u1 + m2 * u2 - m2 * v2/m1]

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