A uniform 2.0kh cylinder of radius .15 m issupended by two strings that are wrap

Question

   A uniform 2.0kh cylinder of radius .15 m issupended by two strings that are wrapped around it. As thecylinder descends, the strings unwind from it. What is theacceleration ofthe center of mass of the cylinder? (Neglect themass of the string). Thank you so much. If you could please be detailed, I'm notquite sure even how to begin.    A uniform 2.0kh cylinder of radius .15 m issupended by two strings that are wrapped around it. As thecylinder descends, the strings unwind from it. What is theacceleration ofthe center of mass of the cylinder? (Neglect themass of the string). Thank you so much. If you could please be detailed, I'm notquite sure even how to begin.

Explanation / Answer

the torque acting on the uniform cylinder is = I * or F * r = I * or = (F * r/I) -----------(1) F = m * g = 2.0 kN = 2.0 * 10^3 N or m = (2.0 * 10^3/g) r = .15 m I = (1/2)m * r^2 substituting the values in equation (1) we get = (m * g * r/(1/2)m * r^2) = (2g/r) g = 9.8 m/s^2 or = (2 * 9.8/.15) = 130.7 rad/s^2

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