A bowling ball on a frictionless pendulum is raised to aheight of 0.20 metres fr

Question

A bowling ball on a frictionless pendulum is raised to aheight of 0.20 metres from its lowest point and released. At the lowest point of its swing the string is cut by asharp blade and the bowling ball falls freely under gravitytill it hits the ground. The mass of the bowling ball is 5.0 kg. a) What is the speed of the bowling ball at the instant thestring is cut? b) If the bowling ball is 0.8 m above the ground when thestring is cut, how far does it travel horizontally, before hittingthe ground? Thanks. A bowling ball on a frictionless pendulum is raised to aheight of 0.20 metres from its lowest point and released. At the lowest point of its swing the string is cut by asharp blade and the bowling ball falls freely under gravitytill it hits the ground. The mass of the bowling ball is 5.0 kg. a) What is the speed of the bowling ball at the instant thestring is cut? b) If the bowling ball is 0.8 m above the ground when thestring is cut, how far does it travel horizontally, before hittingthe ground? Thanks.

Explanation / Answer

a) Using mgh=1/2mv2 find v v=(2gh) v=(2*9.8m/s2*.20m) v=1.98m/s b) find t using d=1/2at2 d=y=0.8m 0.8m=1/2*9.8m/s2*t2 solving for t t=((2*0.8m)/9.8m/s2) t=0.4s find x using x=vxt x=1.98m/s2*0.4s x=0.8m solving for t t=((2*0.8m)/9.8m/s2) t=0.4s find x using x=vxt x=1.98m/s2*0.4s x=0.8m

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