The position of an object connected to a spring varies with timeaccording to the

Question

The position of an object connected to a spring varies with timeaccording to the expression x = (5.3 cm) sin(9.6t). (a) Find the period of this motion.
s

(b) Find the frequency of the motion.
Hz

(c) Find the amplitude of the motion.
cm

(d) Find the first time after t = 0 that the objectreaches the position x = 2.6 cm.
s (a) Find the period of this motion.
s

(b) Find the frequency of the motion.
Hz

(c) Find the amplitude of the motion.
cm

(d) Find the first time after t = 0 that the objectreaches the position x = 2.6 cm.
s

Explanation / Answer

(a)           Period:   T = 2 /    = 2 / 9.6 = 0.208 s (b)         Frequency (f) = / 2   = 9.6 /2   = 4.8 Hz (c)         Amplitude is:   a = 5.3 cm (d)                     2.6 cm = 5.3 cm * sin (9.6 t)         or sin ( 9.6 t) = 2.6/5.3 = 0.490 ˜0.5                   9.6 t = sin-1 ( 0.5) = 30                     or    t     = 30 / 9.6                                   = 0.995 s Hope this helps u!

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.