a 10 F capacitor initially charged to 5 V is dischargedthru a resistance R. The

Question

a 10 F capacitor initially charged to 5 V is dischargedthru a resistance R. The capacitor reaches a potential differenceof 4 V in a period of 3 sec after the charging began. Find thevalue of R. Solution must contain all given values for full credit. Thanks a 10 F capacitor initially charged to 5 V is dischargedthru a resistance R. The capacitor reaches a potential differenceof 4 V in a period of 3 sec after the charging began. Find thevalue of R. Solution must contain all given values for full credit. Thanks

Explanation / Answer

In discharging of RC circuit , Voltage after time t is   v = V e -t / RC given v = 4 Volt         V = 5 Volt         C =Capaciatnce = 10 * 10 ^ -6 F substitue values weget   4 = 5 e -t/ RC from this   -t / RC = ln ( 4 / 5 )                           = -0.2231 from this resistance R = t / ( 0.2231  C ) where t = 3 s Substitue values we get   R = 13.44 * 10 ^ 5ohm                                         = 1.344 M ohm given v = 4 Volt         V = 5 Volt         C =Capaciatnce = 10 * 10 ^ -6 F substitue values weget   4 = 5 e -t/ RC from this   -t / RC = ln ( 4 / 5 )                           = -0.2231 from this resistance R = t / ( 0.2231  C ) where t = 3 s Substitue values we get   R = 13.44 * 10 ^ 5ohm                                         = 1.344 M ohm

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