(a) What is the magnitude of F when the crate is in this final position? 1 N (b)

Question

(a) What is the magnitude of Fwhen the crate is in this final position?
1 N

(b) During the crate's displacement, what is the total work done onit?
2 J

(c) During the crate's displacement, what is the work done by theweight of the crate?
3 kJ

(d) During the crate's displacement, what is the work done by thepull on the crate from the rope?
4 J

(e) Knowing that the crate is motionless before and after itsdisplacement, use the answers to (b), (c), and (d) to find the workyour force F does on the crate.
5 kJ

Explanation / Answer

a)
L^2=R^2+d^2
R=sqrt(L^2-d^2)
R=9.16515139
sin (d/L)=
=23.5781785
tan=F/mg
f=mgtan
220*9.8*tan(23.6)
f=941.933239 N b) vi=vf=0
total work = k = 0
c)
W=-mgy y=L-R=10-9.17=0.83
W=-220*9.8*0.83= -1789.48 J= -1.789kJ
d)
W=0 because T*x=0
e)
Wtotal=Wg+Wt+Wf, Wt=0 & Wtotal=0
Wf=-Wg
Wg= -1.789kJ
Wd= +1.789kJ
c)
W=-mgy y=L-R=10-9.17=0.83
W=-220*9.8*0.83= -1789.48 J= -1.789kJ
d)
W=0 because T*x=0
e)
Wtotal=Wg+Wt+Wf, Wt=0 & Wtotal=0
Wf=-Wg
Wg= -1.789kJ
Wd= +1.789kJ

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